Calculations must be performed by a technician \/ mechanic associated with parallel rangkaiann highly unlikely.<\/span> But no matter how well the properties of parallel circuits should be understood by the technicians \/ mechanics field.<\/span> The current drawn by each branch is determined by the parallel circuit of resistance that exist in the branch circuit.<\/span> The total current drawn by the circuit is the sum of all current parallel branches.<\/span><\/p>\n

Current on each branch of parallel can be calculated using Ohm’s law, if resistannya known.<\/span> The voltage across each parallel branch is always the same, the voltage across the parallel circuit is expressed in the following equation:<\/span><\/p>\n

Ut = U1 = U2 = U3 = U4 = ……<\/strong><\/span><\/p>\n

Total resistance value or the equivalent resistance (RT) of the parallel circuit will lower the value of the smallest resistance in a parallel circuit.<\/span> In mathematics can be written as follows:<\/span><\/p>\n

<\/a><\/p>\n

Because the voltage drop on each load in parallel branches of the same, then the current received by each load in each parallel branch will change depending on the value of the load resistance.<\/span> Flow at branch faithfully inversely proportional to the value resistannya.<\/span> In mathematics can be written as follows:<\/span><\/p>\n

<\/a><\/p>\n

The amount of current in a parallel circuit is equal to the current value on each parallel branch.<\/span> It is expressed in the following equation:<\/span>
\n It = I1 + I2 + I3 + I4 + …… ..<\/strong><\/span>
\n Ohm’s law can be used to calculate the parameters of each element in series or series total.<\/span> 3:41 Picture shows a parallel circuit consisting of two heating elements that have resistance with different values.<\/span> Calculation of total resistance, current, and voltage drop on each load of heating can be done by applying Ohm’s Law as follows:<\/span><\/p>\n

<\/a><\/p>\n

Parallel circuit 3:38 image 2 Resistor<\/span>
\n How to calculate total resistance:<\/strong><\/span>
\n<\/strong> Step 1: Use the formula<\/span><\/p>\n

<\/a><\/p>\n

Step 2: Substitute the resistance value of each resistor<\/span><\/p>\n

<\/a><\/p>\n

Step 3: Keep the same denominator and totalizing<\/span><\/p>\n

<\/a><\/p>\n

Step 4: Complete the equation by reversing the equation<\/span>
\n Rt = 240\/34 = 7:06 ohm<\/span><\/p>\n

How to calculate the total electric current:<\/strong><\/span>
\n To calculate the electric current flowing in a parallel circuit use Ohm’s Law.<\/span>
\n Step 1: Use the formula<\/span><\/p>\n

<\/a><\/p>\n

Step 2: Substitute the value of the voltage (U) and the value of the total resistance (Rt).<\/span><\/p>\n

<\/a><\/p>\n

Step 3: Complete the equation<\/span>
\n It = 31.16 ampere<\/span><\/p>\n

Ohm’s Law to calculate the current of each branch (R1).<\/strong><\/span>
\n<\/strong> Step 1: Use the formula<\/span><\/p>\n

<\/a><\/p>\n

Step 2: Substitute the value of the total current (I) and the first heater element resistance value (R1).<\/span><\/p>\n

<\/a><\/p>\n

Step 3: Complete the equation<\/span>
\n I1 = 22 amperes<\/span><\/p>\n

Calculate the current second branch at R2:<\/strong><\/span>
\n<\/strong> Step 1: Use the formula<\/span><\/p>\n

<\/a><\/p>\n

Step 2: Substitute the value of the voltage (U) and the first heater element resistance value (R2).<\/span><\/p>\n

<\/a><\/p>\n

Step 3: Complete the equation<\/span>
\n I2 = 9.16 amperes<\/span>
\n Calculating the total current total:<\/strong><\/span>
\n<\/strong> Step 1: Use the formula<\/span>
\n It = I1 + I2<\/span>
\n Step 2: Substitute the current value I1 and I2 current values<\/span>
\n It = 22 + 9.16<\/span>
\n Step 3: Complete the equation<\/span>
\n It = 31.16 ampere<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Calculations must be performed by a technician \/ mechanic associated with parallel rangkaiann highly unlikely. But no matter how well the properties of parallel circuits should be understood by the technicians \/ mechanics field. The current drawn by each branch is determined by the parallel circuit of resistance that exist in the branch circuit. The …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2232],"tags":[818,826,822,819,827,824,823,820,821,825],"class_list":["post-638","post","type-post","status-publish","format-standard","hentry","category-english","tag-parallel-circuit","tag-parallel-circuit-advantages","tag-parallel-circuit-calculator","tag-parallel-circuit-definition","tag-parallel-circuit-diagram","tag-parallel-circuit-examples","tag-parallel-circuit-formula","tag-parallel-circuit-problems","tag-parallel-circuit-resistance","tag-parallel-circuit-rules"],"_links":{"self":[{"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/posts\/638","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/comments?post=638"}],"version-history":[{"count":1,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/posts\/638\/revisions"}],"predecessor-version":[{"id":5436,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/posts\/638\/revisions\/5436"}],"wp:attachment":[{"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/media?parent=638"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/categories?post=638"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.tneutron.net\/elektro\/wp-json\/wp\/v2\/tags?post=638"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}