{"id":638,"date":"2023-05-31T05:56:13","date_gmt":"2023-05-30T22:56:13","guid":{"rendered":"http:\/\/www.tneutron.net\/elektro\/?p=638"},"modified":"2023-05-29T14:21:12","modified_gmt":"2023-05-29T07:21:12","slug":"parallel-circuit-characteristics","status":"publish","type":"post","link":"https:\/\/www.tneutron.net\/elektro\/parallel-circuit-characteristics\/","title":{"rendered":"Parallel Circuit Characteristics"},"content":{"rendered":"<p><span class=\"notranslate\">Calculations must be performed by a technician \/ mechanic associated with parallel rangkaiann highly unlikely.<\/span> <span class=\"notranslate\"> But no matter how well the properties of parallel circuits should be understood by the technicians \/ mechanics field.<\/span> <span class=\"notranslate\"> The current drawn by each branch is determined by the parallel circuit of resistance that exist in the branch circuit.<\/span> <span class=\"notranslate\"> The total current drawn by the circuit is the sum of all current parallel branches.<\/span><\/p>\n<p><span class=\"notranslate\"> Current on each branch of parallel can be calculated using Ohm&#8217;s law, if resistannya known.<\/span> <span class=\"notranslate\"> The voltage across each parallel branch is always the same, the voltage across the parallel circuit is expressed in the following equation:<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>Ut = U1 = U2 = U3 = U4 = &#8230;&#8230;<\/strong><\/span><\/p>\n<p><span class=\"notranslate\"> Total resistance value or the equivalent resistance (RT) of the parallel circuit will lower the value of the smallest resistance in a parallel circuit.<\/span> <span class=\"notranslate\"> In mathematics can be written as follows:<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image34.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb35.png\" alt=\"image\" width=\"176\" height=\"52\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Because the voltage drop on each load in parallel branches of the same, then the current received by each load in each parallel branch will change depending on the value of the load resistance.<\/span> <span class=\"notranslate\"> Flow at branch faithfully inversely proportional to the value resistannya.<\/span> <span class=\"notranslate\"> In mathematics can be written as follows:<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image40.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb40.png\" alt=\"image\" width=\"67\" height=\"54\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> The amount of current in a parallel circuit is equal to the current value on each parallel branch.<\/span> <span class=\"notranslate\"> It is expressed in the following equation:<\/span><br \/>\n<span class=\"notranslate\"> <strong>It = I1 + I2 + I3 + I4 + &#8230;&#8230; ..<\/strong><\/span><br \/>\n<span class=\"notranslate\"> Ohm&#8217;s law can be used to calculate the parameters of each element in series or series total.<\/span> <span class=\"notranslate\"> 3:41 Picture shows a parallel circuit consisting of two heating elements that have resistance with different values.<\/span> <span class=\"notranslate\"> Calculation of total resistance, current, and voltage drop on each load of heating can be done by applying Ohm&#8217;s Law as follows:<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image43.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb42.png\" alt=\"image\" width=\"272\" height=\"183\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Parallel circuit 3:38 image 2 Resistor<\/span><br \/>\n<span class=\"notranslate\"> <strong>How to calculate total resistance:<\/strong><\/span> <strong><br \/>\n<\/strong> <span class=\"notranslate\"> Step 1: Use the formula<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image47.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb49.png\" alt=\"image\" width=\"90\" height=\"45\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 2: Substitute the resistance value of each resistor<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image50.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb51.png\" alt=\"image\" width=\"85\" height=\"46\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 3: Keep the same denominator and totalizing<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image52.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb53.png\" alt=\"image\" width=\"136\" height=\"45\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 4: Complete the equation by reversing the equation<\/span><br \/>\n<span class=\"notranslate\"> Rt = 240\/34 = 7:06 ohm<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>How to calculate the total electric current:<\/strong><\/span><br \/>\n<span class=\"notranslate\"> To calculate the electric current flowing in a parallel circuit use Ohm&#8217;s Law.<\/span><br \/>\n<span class=\"notranslate\"> Step 1: Use the formula<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image53.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb54.png\" alt=\"image\" width=\"62\" height=\"45\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 2: Substitute the value of the voltage (U) and the value of the total resistance (Rt).<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image54.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb55.png\" alt=\"image\" width=\"66\" height=\"49\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 3: Complete the equation<\/span><br \/>\n<span class=\"notranslate\"> It = 31.16 ampere<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>Ohm&#8217;s Law to calculate the current of each branch (R1).<\/strong><\/span> <strong><br \/>\n<\/strong> <span class=\"notranslate\"> Step 1: Use the formula<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image55.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb56.png\" alt=\"image\" width=\"57\" height=\"46\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 2: Substitute the value of the total current (I) and the first heater element resistance value (R1).<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image56.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb57.png\" alt=\"image\" width=\"59\" height=\"45\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 3: Complete the equation<\/span><br \/>\n<span class=\"notranslate\"> I1 = 22 amperes<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>Calculate the current second branch at R2:<\/strong><\/span> <strong><br \/>\n<\/strong> <span class=\"notranslate\"> Step 1: Use the formula<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image57.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb58.png\" alt=\"image\" width=\"55\" height=\"49\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 2: Substitute the value of the voltage (U) and the first heater element resistance value (R2).<\/span><\/p>\n<p><a href=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image58.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/www.tneutron.net\/elektro\/wp-content\/uploads\/sites\/2\/2015\/09\/image_thumb59.png\" alt=\"image\" width=\"60\" height=\"42\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Step 3: Complete the equation<\/span><br \/>\n<span class=\"notranslate\"> I2 = 9.16 amperes<\/span><br \/>\n<span class=\"notranslate\"> <strong>Calculating the total current total:<\/strong><\/span> <strong><br \/>\n<\/strong> <span class=\"notranslate\"> Step 1: Use the formula<\/span><br \/>\n<span class=\"notranslate\"> It = I1 + I2<\/span><br \/>\n<span class=\"notranslate\"> Step 2: Substitute the current value I1 and I2 current values<\/span><br \/>\n<span class=\"notranslate\"> It = 22 + 9.16<\/span><br \/>\n<span class=\"notranslate\"> Step 3: Complete the equation<\/span><br \/>\n<span class=\"notranslate\"> It = 31.16 ampere<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Calculations must be performed by a technician \/ mechanic associated with parallel rangkaiann highly unlikely. But no matter how well the properties of parallel circuits should be understood by the technicians \/ mechanics field. The current drawn by each branch is determined by the parallel circuit of resistance that exist in the branch circuit. The &#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2232],"tags":[818,826,822,819,827,824,823,820,821,825],"class_list":["post-638","post","type-post","status-publish","format-standard","hentry","category-english","tag-parallel-circuit","tag-parallel-circuit-advantages","tag-parallel-circuit-calculator","tag-parallel-circuit-definition","tag-parallel-circuit-diagram","tag-parallel-circuit-examples","tag-parallel-circuit-formula","tag-parallel-circuit-problems","tag-parallel-circuit-resistance","tag-parallel-circuit-rules"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.3 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Parallel Circuit Characteristics - TN Elektro<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.tneutron.net\/elektro\/parallel-circuit-characteristics\/\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:title\" content=\"Parallel Circuit Characteristics - TN Elektro\" \/>\n<meta name=\"twitter:description\" content=\"Calculations must be performed by a technician \/ mechanic associated with parallel rangkaiann highly unlikely. 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