{"id":1577,"date":"2024-12-10T01:54:32","date_gmt":"2024-12-09T18:54:32","guid":{"rendered":"https:\/\/www.tneutron.net\/industri\/?p=1577"},"modified":"2024-12-06T09:01:49","modified_gmt":"2024-12-06T02:01:49","slug":"venn-diagram","status":"publish","type":"post","link":"https:\/\/www.tneutron.net\/industri\/venn-diagram\/","title":{"rendered":"Venn Diagram"},"content":{"rendered":"<p><span class=\"notranslate\">One way to make it easier to describe the relationship between the variables in the boolean algebra is to use a Venn diagram.<\/span> <span class=\"notranslate\"> This diagram consists of a quadrangle inside painted circles represent variables, one circle for each variable.<\/span> <span class=\"notranslate\"> Each circle was named by the variable represents.<\/span> <span class=\"notranslate\"> Determined that all points outside the circle was not owned by these variables.<\/span><\/p>\n<p><span class=\"notranslate\"> For example, a circle with the name of A, if the circle is said to be worth 1, then beyond a said to be worth 0. for two circles that overlap, there are four areas within the quadrilateral.<\/span><br \/>\n<a href=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image-1.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image_thumb-1.png\" alt=\"image\" width=\"244\" height=\"189\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\">Venn diagrams can be used to describe the boolean algebra postulate or to prove entry into force of Boolean algebra.<\/span> <span class=\"notranslate\"> The following figure shows that the area is owned by AB is located in the loop A so that A + A = A.<\/span><br \/>\n<a href=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image-2.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image_thumb-2.png\" alt=\"image\" width=\"191\" height=\"144\" border=\"0\" \/><\/a><br \/>\n<span class=\"notranslate\"> The following figure, shows the distributive law A (B + C) = AB + AC<\/span><\/p>\n<p><a href=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image-4.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"https:\/\/www.tneutron.net\/industri\/wp-content\/uploads\/sites\/3\/2016\/11\/image_thumb-4.png\" alt=\"image\" width=\"197\" height=\"203\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\">In the circle appears three overlapping circles, one for each of the variables A, B and C. so it is possible to distinguish eight separate area in the venn diagram with that variable.<\/span> <span class=\"notranslate\"> In this case the law distributiv proved by showing that the area that intersects the circle A with an area that includes B or C is the same area which is owned by AB or A.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>One way to make it easier to describe the relationship between the variables in the boolean algebra is to use<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"colormag_page_container_layout":"default_layout","colormag_page_sidebar_layout":"default_layout","footnotes":""},"categories":[1830],"tags":[1967,1975,1971,1973,1968,1974,1970,1976,1969,1972],"class_list":["post-1577","post","type-post","status-publish","format-standard","hentry","category-english","tag-venn-diagram","tag-venn-diagram-creator","tag-venn-diagram-definition","tag-venn-diagram-excel","tag-venn-diagram-maker","tag-venn-diagram-math","tag-venn-diagram-pdf","tag-venn-diagram-powerpoint","tag-venn-diagram-template","tag-venn-diagram-worksheet"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.8 - 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