If there are two forces that have captured the same point a different direction with the direction of the force makes an angle \u03b1 the resultant number can be calculated by the following equation:<\/span><\/p>\n Figure 2.23 Two styles with different directions<\/span><\/p>\n For \u03b1 = 90 \u00b0<\/sup> then Cos \u03b1 = 0 or apply the formula of Pythagoras, namely:<\/span><\/p>\n Description :<\/span> Compiling Style Located In The Flat Field<\/strong><\/span> Figure 2.26 Two different styles to capture titk<\/span><\/p>\n Of both style over specified:<\/span> Completion See the following picture:<\/span>
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\n o P and Q = component force<\/span>
\n o \u03b1 = angle of the wedge between the two styles<\/span>
\n o R = Resultant<\/span><\/p>\n
\n If there are two forces that have a different fishing spot and is located on a flat, then to determine the capture point style can be implemented in two ways:<\/span>
\n o by way of painting.<\/span>
\n o by way of analysis \/ count<\/span>
\n Example: Two forces each has a capture point at point A and point B with the distance AB = 60 cm, a large force P = 8 N and the direction of his style left under an angle of 120 \u00b0<\/sup> to the horizontal line, Style Q = 2 \u221a3 N with direction of the force perpendicular to the bottom, see the following picture:<\/span><\/p>\n
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\n – The magnitude of the resultant;<\/span>
\n – Directions resultant;<\/span>
\n – Point the resultant catch<\/span><\/p>\n
\n To determine the point of capture, the direction and magnitude of the resultant force can be done by way of painting is as follows:<\/span>
\n – Copy the above questions with a scale of 2 N # 1cm style and length scales of 1: 10.<\/span>
\n – Extend the line of force P and Q upwards to meet at a point C.<\/span>
\n – Move the force P and Q to point C.<\/span>
\n – Create parallelogram through force P and Q are.<\/span>
\n – Create diagonally through point C to obtain the magnitude of the resultant R.<\/span>
\n – Extend the working line style R to cut the line AB at point D, and point D is the point of the resultant catch.<\/span>
\n – Move resultant from point C to point D capture.<\/span> Then obtained: the point of capture, the direction and magnitude of the resultant force as shown in the following figure.<\/span><\/p>\n