{"id":471,"date":"2024-10-16T05:02:40","date_gmt":"2024-10-15T22:02:40","guid":{"rendered":"http:\/\/www.tneutron.net\/mesin\/?p=471"},"modified":"2024-10-11T08:15:23","modified_gmt":"2024-10-11T01:15:23","slug":"moment-of-inertia","status":"publish","type":"post","link":"https:\/\/www.tneutron.net\/mesin\/moment-of-inertia\/","title":{"rendered":"Moment of Inertia"},"content":{"rendered":"<p><span class=\"notranslate\"><strong>a. <a href=\"http:\/\/translate.googleusercontent.com\/translate_c?depth=1&amp;hl=en&amp;rurl=translate.google.com&amp;sl=id&amp;tl=en&amp;u=http:\/\/www.tneutron.net\/mesin\/momen-inersia\/&amp;usg=ALkJrhiISSBz3CXqJEH5oDvIcecN91-0Xg\">Moment of Inertia<\/a> Against Horizontal axis (XX)<\/strong><\/span><br \/>\n<span class=\"notranslate\"> Moment of inertia of the cross section to a line that is the number of cross-sectional area (element) multiplied by the square of the smallest normal distance to the EAM, or cross-sectional area multiplied by the square of the distance.<\/span> <span class=\"notranslate\"> If the cross-sectional area is the smallest elements DA1, DA2, dA3 &#8230;.<\/span> <span class=\"notranslate\"> and and the distance of the cross section to the XX line is y1, y2, y3 &#8230;&#8230; yn, then the cross-sectional moment of inertia about the line XX can be written by the following equation:<\/span><br \/>\n<span class=\"notranslate\"> <strong>Ix = AY <sup>2<\/sup><\/strong><\/span><\/p>\n<p><span class=\"notranslate\"> See the following picture<\/span><\/p>\n<p><a href=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image30.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/i1.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image_thumb29.png?resize=265%2C246\" alt=\"image\" width=\"265\" height=\"246\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Figure 5.2 The moment of inertia about the axis x<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>b.<\/strong><\/span> <span class=\"notranslate\"> <strong>Moment of Inertia Against Lines Vertical axis (YY)<\/strong><\/span><br \/>\n<span class=\"notranslate\"> If the cross-sectional area is the smallest elements DA1, DA2, dA3 &#8230;.<\/span> <span class=\"notranslate\"> and and the distance of the cross section to line YY is the X1, X2, X3 &#8230;&#8230; Xn, then the cross-sectional moment of inertia about the line YY can be written by the following equation:<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>Iy = AX <sup>2<\/sup><\/strong><\/span><\/p>\n<p><span class=\"notranslate\"> See the following page image<\/span><\/p>\n<p><a href=\"http:\/\/i1.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image33.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/i2.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image_thumb32.png?resize=282%2C267\" alt=\"image\" width=\"282\" height=\"267\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Figure 5.3 The moment of inertia about the axis y<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>c.<\/strong><\/span> <span class=\"notranslate\"> <strong>Polar Moment of Inertia<\/strong><\/span><br \/>\n<span class=\"notranslate\"> Namely polar moment of inertia of the cross-sectional moment of inertia of a point or the intersection of the axes of XX and YY axis, the amount is calculated based on the number-smallest cross-sectional area multiplied by the square of the radius or distance of the point normal weight.<\/span> <span class=\"notranslate\"> If the cross-sectional area is the smallest elements DA1, DA2, dA3 &#8230;.<\/span> <span class=\"notranslate\"> and the cross-section and the distance from the cut point to axis X, Y are r1, r2, r3 &#8230;&#8230; rn, then the polar moment of inertia can be written by the following equation:<\/span><\/p>\n<p><span class=\"notranslate\"> <strong>Ip = Ar <sup>2<\/sup><\/strong><\/span><\/p>\n<p><span class=\"notranslate\"> <strong>L<\/strong> Ihat picture following page.<\/span><\/p>\n<p><a href=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image37.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image_thumb38.png?resize=275%2C231\" alt=\"image\" width=\"275\" height=\"231\" border=\"0\" \/><\/a> <a href=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image42.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image_thumb42.png?resize=196%2C181\" alt=\"image\" width=\"196\" height=\"181\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Figure 5.4 polar moment of inertia<\/span><\/p>\n<p><span class=\"notranslate\"> According Phitagoras:<\/span><br \/>\n<span class=\"notranslate\"> <strong>r <sup>2<\/sup> = x <sup>2<\/sup> + y <sup>2<\/sup><\/strong><\/span><\/p>\n<p><span class=\"notranslate\"> Then<\/span><br \/>\n<span class=\"notranslate\"> <strong>Ix = Iz + A.<\/strong><\/span> <span class=\"notranslate\"> <strong>A <sup>2<\/sup><\/strong><\/span><\/p>\n<p><a href=\"http:\/\/i0.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image46.png\"><img loading=\"lazy\" decoding=\"async\" title=\"image\" src=\"http:\/\/i2.wp.com\/www.tneutron.net\/mesin\/wp-content\/uploads\/sites\/4\/2015\/08\/image_thumb45.png?resize=322%2C293\" alt=\"image\" width=\"322\" height=\"293\" border=\"0\" \/><\/a><\/p>\n<p><span class=\"notranslate\"> Figure 5.5 The moment of inertia of a cross-section<\/span><\/p>\n<p><span class=\"notranslate\"> Description :<\/span><br \/>\n<span class=\"notranslate\"> Iz = moment of inertia of its own cross-section through the EAM<\/span><br \/>\n<span class=\"notranslate\"> Ix = moment of inertia to a line xx in units CM4.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>a. Moment of Inertia Against Horizontal axis (XX) Moment of inertia of the cross section to a line that is<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"colormag_page_container_layout":"default_layout","colormag_page_sidebar_layout":"default_layout","footnotes":""},"categories":[1406],"tags":[458,465,460,462,463,466,461,459,467,464],"class_list":["post-471","post","type-post","status-publish","format-standard","hentry","category-english","tag-moment-inertia","tag-moment-inertia-calculator","tag-moment-inertia-circle","tag-moment-inertia-cylinder","tag-moment-inertia-disk","tag-moment-inertia-pipe","tag-moment-inertia-rod","tag-moment-inertia-sphere","tag-moment-inertia-tube","tag-moment-inertia-units"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.9 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Moment of Inertia - TN Mesin<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.tneutron.net\/mesin\/moment-of-inertia\/\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:title\" content=\"Moment of Inertia - TN Mesin\" \/>\n<meta name=\"twitter:description\" content=\"a. 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