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{"id":471,"date":"2024-10-16T05:02:40","date_gmt":"2024-10-15T22:02:40","guid":{"rendered":"http:\/\/www.tneutron.net\/mesin\/?p=471"},"modified":"2024-10-11T08:15:23","modified_gmt":"2024-10-11T01:15:23","slug":"moment-of-inertia","status":"publish","type":"post","link":"https:\/\/www.tneutron.net\/mesin\/moment-of-inertia\/","title":{"rendered":"Moment of Inertia"},"content":{"rendered":"

a. Moment of Inertia<\/a> Against Horizontal axis (XX)<\/strong><\/span>
\n Moment of inertia of the cross section to a line that is the number of cross-sectional area (element) multiplied by the square of the smallest normal distance to the EAM, or cross-sectional area multiplied by the square of the distance.<\/span> If the cross-sectional area is the smallest elements DA1, DA2, dA3 ….<\/span> and and the distance of the cross section to the XX line is y1, y2, y3 …… yn, then the cross-sectional moment of inertia about the line XX can be written by the following equation:<\/span>
\n Ix = AY 2<\/sup><\/strong><\/span><\/p>\n

See the following picture<\/span><\/p>\n

\"image\"<\/a><\/p>\n

Figure 5.2 The moment of inertia about the axis x<\/span><\/p>\n

b.<\/strong><\/span> Moment of Inertia Against Lines Vertical axis (YY)<\/strong><\/span>
\n If the cross-sectional area is the smallest elements DA1, DA2, dA3 ….<\/span> and and the distance of the cross section to line YY is the X1, X2, X3 …… Xn, then the cross-sectional moment of inertia about the line YY can be written by the following equation:<\/span><\/p>\n

Iy = AX 2<\/sup><\/strong><\/span><\/p>\n

See the following page image<\/span><\/p>\n

\"image\"<\/a><\/p>\n

Figure 5.3 The moment of inertia about the axis y<\/span><\/p>\n

c.<\/strong><\/span> Polar Moment of Inertia<\/strong><\/span>
\n Namely polar moment of inertia of the cross-sectional moment of inertia of a point or the intersection of the axes of XX and YY axis, the amount is calculated based on the number-smallest cross-sectional area multiplied by the square of the radius or distance of the point normal weight.<\/span> If the cross-sectional area is the smallest elements DA1, DA2, dA3 ….<\/span> and the cross-section and the distance from the cut point to axis X, Y are r1, r2, r3 …… rn, then the polar moment of inertia can be written by the following equation:<\/span><\/p>\n

Ip = Ar 2<\/sup><\/strong><\/span><\/p>\n

L<\/strong> Ihat picture following page.<\/span><\/p>\n

\"image\"<\/a> \"image\"<\/a><\/p>\n

Figure 5.4 polar moment of inertia<\/span><\/p>\n

According Phitagoras:<\/span>
\n r 2<\/sup> = x 2<\/sup> + y 2<\/sup><\/strong><\/span><\/p>\n

Then<\/span>
\n Ix = Iz + A.<\/strong><\/span> A 2<\/sup><\/strong><\/span><\/p>\n

\"image\"<\/a><\/p>\n

Figure 5.5 The moment of inertia of a cross-section<\/span><\/p>\n

Description :<\/span>
\n Iz = moment of inertia of its own cross-section through the EAM<\/span>
\n Ix = moment of inertia to a line xx in units CM4.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

a. Moment of Inertia Against Horizontal axis (XX) Moment of inertia of the cross section to a line that is the number of cross-sectional area (element) multiplied by the square of the smallest normal distance to the EAM, or cross-sectional area multiplied by the square of the distance. If the cross-sectional area is the smallest …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1406],"tags":[458,465,460,462,463,466,461,459,467,464],"class_list":["post-471","post","type-post","status-publish","format-standard","hentry","category-english","tag-moment-inertia","tag-moment-inertia-calculator","tag-moment-inertia-circle","tag-moment-inertia-cylinder","tag-moment-inertia-disk","tag-moment-inertia-pipe","tag-moment-inertia-rod","tag-moment-inertia-sphere","tag-moment-inertia-tube","tag-moment-inertia-units"],"_links":{"self":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/471","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/comments?post=471"}],"version-history":[{"count":1,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/471\/revisions"}],"predecessor-version":[{"id":3150,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/471\/revisions\/3150"}],"wp:attachment":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/media?parent=471"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/categories?post=471"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/tags?post=471"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}