Terms of balance to the force components that have the same capture point to different directions, is<\/span>
\n o The amount of force on the X axis = zero (\u03a3X = 0);<\/span>
\n o The amount of force on the Y axis = zero.<\/span> (\u03a3Y = 0).<\/span><\/p>\n

As for the style of a style that has a different fishing spot, where the force of the catch point to the other capture points have a certain distance, giving rise to the moment, by because they were for the force components that have different capture points apart \u03a3X = 0;<\/span> \u03a3Y = 0.<\/span> Also the amount of torque at a point equal to zero or can be written \u03a3M = 0.<\/span> Also the number of action force equal to the amount of reaction force.<\/span>
\n Description :<\/span>
\n o is the reaction force opposing force with force action,<\/span>
\n o The action force is equal to the amount of reaction force<\/span>
\n o The amount of force the action with reaction force equal to zero,<\/span><\/p>\n

See the following page image<\/span><\/p>\n

<\/a><\/p>\n

Figure 3.6 The style of action and reaction<\/span><\/p>\n

Capture Point determine Resultant By Moment<\/strong><\/span>
\n To determine the point of arrest and the magnitude of the force resultane style that has the same direction with a different point of capture can be done by means of analysis and the way of painting.<\/span> Method of analysis to determine R, namely:<\/span>
\n R = P + Q<\/strong><\/span>
\n Whereas to determine the resultant capture point, which is the distance from one point to capture the style \/ resultant moment is by using the equation, namely Total moments style to a point equal to aya resultant X distance to that point, see the following picture:<\/span><\/p>\n

<\/a><\/p>\n

Figure 3.9 The resultant two styles in the same direction<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Terms of balance to the force components that have the same capture point to different directions, is o The amount of force on the X axis = zero (\u03a3X = 0); o The amount of force on the Y axis = zero. (\u03a3Y = 0). As for the style of a style that has a …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1406],"tags":[522,531,526,530,523,532,527,525,529,524,528],"class_list":["post-485","post","type-post","status-publish","format-standard","hentry","category-english","tag-calculating-moment","tag-calculating-moment-about-an-axis","tag-calculating-moment-arm","tag-calculating-moment-magnitude","tag-calculating-moment-of-inertia","tag-calculating-moment-of-inertia-of-a-disk","tag-calculating-moment-of-inertia-of-a-rod","tag-calculating-moments","tag-calculating-moments-in-3d","tag-calculating-momentum","tag-calculating-momentum-finance"],"_links":{"self":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/485","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/comments?post=485"}],"version-history":[{"count":1,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/485\/revisions"}],"predecessor-version":[{"id":3157,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/posts\/485\/revisions\/3157"}],"wp:attachment":[{"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/media?parent=485"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/categories?post=485"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.tneutron.net\/mesin\/wp-json\/wp\/v2\/tags?post=485"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}